Download Technician's Guide to the 68HC11 Microcontroller by Dan Black, Leo Chartrand PDF

By Dan Black, Leo Chartrand

ISBN-10: 0766817156

ISBN-13: 9780766817159

Technician's advisor to the 68HC11 Microcontroller is perfect for readers with very little past programming adventure who are looking to grasp the fundamentals of troubleshooting and programming Motorola's 68HC11 microcontroller. either and software program are lined intimately to supply a whole figuring out of the rules underlying how a microcontroller works. idea is supplemented by means of examples designed to demonstrate how techniques will be utilized. through studying easy methods to software the 68HC11 at an easy point, readers additionally achieve necessary adventure utilizing manufacturer-specific documentation that prepares them for paintings with different extra subtle microcontrollers.

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Extra info for Technician's Guide to the 68HC11 Microcontroller

Sample text

Dd is loaded into Temp16L. Temp16H is cleared. Contents of Temp16 are copied to MAR. (PC) → MAR $0107 → MAR (PC) + 1 → PC $0108 → PC ($0107) → data bus $20 → data bus Operand is retrieved from AccA. Operand is loaded into memory. 4 1. What is the function of a fetch cycle? 2. What takes place during the execute cycles of an instruction? 3. How does Motorola store 16-bit data in memory? 5 Program Flow Programs can be written to perform a variety of tasks. The flow of a program is determined by the instructions used to implement the program.

Cycles = 4, 1 fetch and 3 executes. 5 Problem: Draw flowchart and write the program that will copy a single byte from $0100 to $0180. Assemble the code, starting at location $0000. Solution: In order to copy a byte from one memory location to another, the byte must be loaded into a processor register and then stored to the new location.

STY $0123 d. STAA $B600 Solution: a. Bytes = 2. STAB DIR will occupy two bytes; the first byte is the opcode and the second is the low byte of the effective address (dd). Opcode = $D7. Cycles = 3, 1 fetch and 2 executes. b. Bytes = 2. STX DIR will occupy two bytes; the first byte is the opcode and the second is the low byte of the first effective address (dd). Opcode = $DF. Cycles = 4, 1 fetch and 3 executes. c. Bytes = 4. STY EXT will occupy four bytes; the first byte is the prebyte, the second is the opcode and the last two are the first effective address of the operand (hhll).

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