By Thomas Kreis
ISBN-10: 3527405461
ISBN-13: 9783527405466
ISBN-10: 3527604154
ISBN-13: 9783527604159
The ebook provides the rules and techniques of holographic interferometry - a coherent-optical size method for deformation and pressure research, for the decision of refractive-index distributions, or utilized to non-destructive checking out. Emphasis of the ebook is at the quantitative computer-aided evaluate of the holographic interferograms. dependent upon wave-optics the review tools, their implementation in computer-algorithms, and their purposes in engineering are defined.
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Extra info for Handbook of holographic interferometry: optical and digital methods
Example text
The distance from S to P is rSP and that from P to B is rP B . The unit vectors in the corresponding directions are rSP and rP B , and n is the normal to the aperture. The angle between the unit vectors rSP and n is (rSP , n), the angle (rP B , n) is defined analogously. With these notations the field at the observation point B is given by the Fresnel-Kirchhoff diffraction formula E(B) = iE0 λ Σ e−ik(rSP + rP B ) cos(rSP , n) − cos(rP B , n) dx dy. 67) rSP rP B 2 Here it has been assumed that k 1/rP B , meaning an observation point many optical wavelengths apart from the aperture.
132) is the zeroth diffraction order, also called dc-term; it is only the reference wave multiplied with the mean transmittance. 133) despite the multiplicative factor is a conjugated image of the object wave. While the original wavefront was a diverging one from P , the conjugate is a converging wavefront, which 42 2 Optical Foundations of Holography converges to a focus. The image is real and pseudoscopic, the latter describes the property of inverted depths: Parts of the object in the background now appear in the foreground and vice versa, which gives curious parallax effects, difficult to observe.
23. 23: Locations of reconstructed images. 135), leaves the hologram plate in direction −γ1 . To find the second term, we observe that in the hologram plane (z = 0) with EP (x, 0, 0) = exp(ikx sin γ2 ) the conjugate is EP∗ (x, 0, 0) = exp(−ikx sin γ2 ) = exp[ikx sin(−γ2 )]. A conjugate wave would leave the hologram under −γ2 . The square of ER = exp[ikx sin(−γ1 )] is 2 (x, 0, 0) = e−ikx2 sin γ1 . 135) is 2 ∗ EP = e−ikx2 sin γ1 e−ikx sin γ2 = eikx sin(−γ3 ) . 139) For small γ1 we observe that 2 sin γ1 ≈ sin 2γ1 , but always 2 sin γ1 > sin 2γ1 .